Geometry puzzle

 Posts: 20795
 Joined: Wed Jun 09, 2004 11:46 pm
 Title: Bruce of all Bruces
 Location: Massachusetts
Re: Geometry puzzle
Interesting. The answer must be between 6 and 10. Depends on the degree of overlap in the x and y directions and diameters of the circles. Looks like the degree of overlap in the y direction is 2, but I haven't found a way to solve the other three parameters. Will have to chew on it some more later.

 Posts: 23535
 Joined: Sun Jul 18, 2004 7:15 pm
 Title: Incipient toppler
 Location: Swimming in Lake Ed

 Posts: 19888
 Joined: Sat Aug 12, 2006 2:01 am
 Title: Je suis devenu Français
 Location: USA

 Posts: 19888
 Joined: Sat Aug 12, 2006 2:01 am
 Title: Je suis devenu Français
 Location: USA

 Posts: 1472
 Joined: Wed Jun 02, 2004 11:04 pm
 Location: UK
Re: Geometry puzzle
Nope. It's not a square. There's no trick.
Break out your drawing instruments and draw it as accurately as you can  then you can measure x to a decent degree of accuracy.
Those of you who know how can draw it using a CAD program, and so measure x very accurately.
But the best way is to use mathematics or geometry. It's not that difficult.
Break out your drawing instruments and draw it as accurately as you can  then you can measure x to a decent degree of accuracy.
Those of you who know how can draw it using a CAD program, and so measure x very accurately.
But the best way is to use mathematics or geometry. It's not that difficult.

 Posts: 30167
 Joined: Wed Mar 19, 2008 5:45 am
 Location: Yokohama/Tokyo, Japan
Re: Geometry puzzle
By eyeball x > 8.
Can we assume all angles are right angles?
I don't understand the significance of the line segment of length 6. Is it given that this line is parallel to the others? I.e., that the vertical lines are all parallel and the horizontal lines are perpendicular to the vertical lines? Can we further assume that the line segment of length 6 passes through the point where the two circles touch?
Can we assume all angles are right angles?
I don't understand the significance of the line segment of length 6. Is it given that this line is parallel to the others? I.e., that the vertical lines are all parallel and the horizontal lines are perpendicular to the vertical lines? Can we further assume that the line segment of length 6 passes through the point where the two circles touch?

 Posts: 19888
 Joined: Sat Aug 12, 2006 2:01 am
 Title: Je suis devenu Français
 Location: USA

 Posts: 19888
 Joined: Sat Aug 12, 2006 2:01 am
 Title: Je suis devenu Français
 Location: USA
Re: Geometry puzzle
If you square a circle then add another circle, and square them both, its always a square

 Posts: 19888
 Joined: Sat Aug 12, 2006 2:01 am
 Title: Je suis devenu Français
 Location: USA

 Posts: 1472
 Joined: Wed Jun 02, 2004 11:04 pm
 Location: UK
Re: Geometry puzzle
Yes x > 8.Anaxagoras wrote: ↑Wed Sep 16, 2020 10:30 am By eyeball x > 8.
Can we assume all angles are right angles?
I don't understand the significance of the line segment of length 6. Is it given that this line is parallel to the others? I.e., that the vertical lines are all parallel and the horizontal lines are perpendicular to the vertical lines? Can we further assume that the line segment of length 6 passes through the point where the two circles touch?
The outer rectangle is a true rectangle (rightangled corners and straight sides) with short side length 8.
The two circles are true circles. They touch each other tangentially (just touch without overlapping). One circle tangentially touches one short side and one long side of the rectangle, the other circle tangentially touches the remaining two sides.
The line shown with length 6 is parallel to the short sides of the rectangle. The line's ends are points on the circles, and the line passes through the point where the circles touch.

 Posts: 19888
 Joined: Sat Aug 12, 2006 2:01 am
 Title: Je suis devenu Français
 Location: USA

 Posts: 1472
 Joined: Wed Jun 02, 2004 11:04 pm
 Location: UK

 Posts: 30167
 Joined: Wed Mar 19, 2008 5:45 am
 Location: Yokohama/Tokyo, Japan
Re: Geometry puzzle
Yeah, there may be some principle of geometry that allows one to solve for x, but I don't know what it is.

 Posts: 1472
 Joined: Wed Jun 02, 2004 11:04 pm
 Location: UK
Re: Geometry puzzle
Most people would agree that the Pythagorean theorem is a fundamental part of geometry. As Abdul suggested, the trick with most of these sorts of puzzle is to draw a few lines and then apply Pythagoras. The real trick is to know which lines to draw!Anaxagoras wrote: ↑Wed Sep 16, 2020 3:30 pm Yeah, there may be some principle of geometry that allows one to solve for x, but I don't know what it is.

 Posts: 7346
 Joined: Thu Jun 10, 2004 12:16 pm
 Title: inbred shitforbrains
 Location: Planet X
Re: Geometry puzzle
Interesting that ceptimus posted this over at ISF this morning and had two correct answers in less than an hour. I'll draw no conclusions.

 Posts: 30167
 Joined: Wed Mar 19, 2008 5:45 am
 Location: Yokohama/Tokyo, Japan
Re: Geometry puzzle
Without looking for the answer I'm going to guess that it's 9, but I can't show my work.
Either that or it's not a whole number.
Either that or it's not a whole number.

 Posts: 661
 Joined: Sat Dec 23, 2017 4:30 pm
Re: Geometry puzzle
Abdul Alhazred wrote: ↑Thu Sep 17, 2020 3:13 pmIt's our old buddy correlation with population size at work.
More high school geometry students available? :wink:

 Posts: 19888
 Joined: Sat Aug 12, 2006 2:01 am
 Title: Je suis devenu Français
 Location: USA

 Posts: 19888
 Joined: Sat Aug 12, 2006 2:01 am
 Title: Je suis devenu Français
 Location: USA

 Posts: 35689
 Joined: Thu Sep 19, 2013 5:50 pm
Re: Geometry puzzle
A back of the envelope calculation gives me 9. If that's correct I'll write up my solution. (If not I'll just hang my head in shame.)

 Posts: 19888
 Joined: Sat Aug 12, 2006 2:01 am
 Title: Je suis devenu Français
 Location: USA
Re: Geometry puzzle
I’m an idiot
Last edited by robinson on Sat Sep 19, 2020 6:05 am, edited 1 time in total.

 Posts: 1472
 Joined: Wed Jun 02, 2004 11:04 pm
 Location: UK

 Posts: 35689
 Joined: Thu Sep 19, 2013 5:50 pm

 Posts: 19888
 Joined: Sat Aug 12, 2006 2:01 am
 Title: Je suis devenu Français
 Location: USA

 Posts: 19888
 Joined: Sat Aug 12, 2006 2:01 am
 Title: Je suis devenu Français
 Location: USA
Re: Geometry puzzle
It's like posting the Riemann Hypothesis in a puzzle forum. Then laughing like a maniac later that night.

 Posts: 1472
 Joined: Wed Jun 02, 2004 11:04 pm
 Location: UK
Re: Geometry puzzle
Here's a simple geometric proof by Pan Narrans (a poster at the Freethought Forum). Pan was actually the first poster to solve my posting of the puzzle, but I posted the puzzle there about the same time as here, and before I did at ISF, so the ISF guys were the fastest. I didn't invent the puzzle by the way  I first saw it posed in a YouTube "recommended for you" still  but I didn't watch the video and solved it myself instead.
AD = AE = AG = AK (the radius of the small circle)
similarly
BD = BF = BH = BL (the radius of the large circle)
Triangle ADK is an isosceles triangle, with A as its apex. The same goes for triangle BDL, with apex B. The "bases" of the two isosceles triangles (the non equal sides) are KD and DL. Note that the line AC is the same length as half the base of the small triangle plus half the base of the large triangle
AC = (KD + DL)/2, and we know that KD + DL = 6, so AC = 3
Now AG + AC + BH = 8 (the height of the rectangle)
Subtracting AC = 3 gives AG + BH = 5 (the sum of the radii)
Since AD + BD = AG + BH = 5, we have a 3/4/5 right triangle ABC with a hypotenuse (AB) 5 and one side (AC) 3, the other side (BC) must be 4.
X = AE + BF + BC = AG + BH + BC = 5 + 4 = 9
Pan did a clever proof using trigonometry and simultaneous equations, similar to Witness's, first, but then followed it up with this simpler geometric one.
The way I did it was something of a cheat. I reasoned that the puzzle wouldn't have been set unless it had a neat constant answer  not some horrible formula depending on the sizes of the circles drawn. So I figured I could make the smaller circle as small as I wanted without changing the answer. If you draw it with the small circle diameter zero, then you just have a rectangle with short side 8, and the large circle touching the bottom and right hand side of the rectangle and passing through the top left hand corner. The left hand edge of rectangle cuts a chord length 6 across the circle. Then the 3.4.5 triangle is immediately obvious, and you get the solution in a flash.
AD = AE = AG = AK (the radius of the small circle)
similarly
BD = BF = BH = BL (the radius of the large circle)
Triangle ADK is an isosceles triangle, with A as its apex. The same goes for triangle BDL, with apex B. The "bases" of the two isosceles triangles (the non equal sides) are KD and DL. Note that the line AC is the same length as half the base of the small triangle plus half the base of the large triangle
AC = (KD + DL)/2, and we know that KD + DL = 6, so AC = 3
Now AG + AC + BH = 8 (the height of the rectangle)
Subtracting AC = 3 gives AG + BH = 5 (the sum of the radii)
Since AD + BD = AG + BH = 5, we have a 3/4/5 right triangle ABC with a hypotenuse (AB) 5 and one side (AC) 3, the other side (BC) must be 4.
X = AE + BF + BC = AG + BH + BC = 5 + 4 = 9
Pan did a clever proof using trigonometry and simultaneous equations, similar to Witness's, first, but then followed it up with this simpler geometric one.
The way I did it was something of a cheat. I reasoned that the puzzle wouldn't have been set unless it had a neat constant answer  not some horrible formula depending on the sizes of the circles drawn. So I figured I could make the smaller circle as small as I wanted without changing the answer. If you draw it with the small circle diameter zero, then you just have a rectangle with short side 8, and the large circle touching the bottom and right hand side of the rectangle and passing through the top left hand corner. The left hand edge of rectangle cuts a chord length 6 across the circle. Then the 3.4.5 triangle is immediately obvious, and you get the solution in a flash.

 Posts: 20795
 Joined: Wed Jun 09, 2004 11:46 pm
 Title: Bruce of all Bruces
 Location: Massachusetts
Re: Geometry puzzle
Finally got it. Messy and convoluted, but it works. That was fun.
https://i.imgur.com/60UQlA6.jpg
https://i.imgur.com/60UQlA6.jpg

 Posts: 20795
 Joined: Wed Jun 09, 2004 11:46 pm
 Title: Bruce of all Bruces
 Location: Massachusetts

 Posts: 7346
 Joined: Thu Jun 10, 2004 12:16 pm
 Title: inbred shitforbrains
 Location: Planet X